2x^2+60x-900=0

Solution for 2x^2+60x-900=0 equation:

2x^2+60x-900=0

a = 2; b = 60; c = -900;
Δ = b2-4ac
Δ = 602-4·2·(-900)
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{3}}{2*2}=\frac{-60-60\sqrt{3}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{3}}{2*2}=\frac{-60+60\sqrt{3}}{4}
$